Q. The unpaired electron in $ Ni(CO)_{4} $ is
AMUAMU 2013Coordination Compounds
Solution:
In $N i(C O)_{4}$, there is no unpaired electron.
It is diamagnetic.
Oxidation state of $N i$ in $\left[N i(C O)_{4}\right]$
complex compound is zero.
$N i=3 d^{8} 4 s^{2}$
$s p^{3}$ hybridised orbitals of $Ni$
$\left[N i(C O)_{4}\right]$
