Q. The unit of thermal conductance is

1297 188 VMMC MedicalVMMC Medical 2008 Report Error

A

$W K^{- 1}$

B

$J K^{- 1}$

C

WK

D

JK

Solution:

Thermal conductance $= \frac{Δ Q}{t Δ θ}$ $= \frac{J}{sK}$ $= \frac{J}{s} K^{- 1}$ $= W K^{- 1}$