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  4. The unit of thermal conductance is

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Q. The unit of thermal conductance is

VMMC MedicalVMMC Medical 2008

Solution:

Thermal conductance $ =\frac{\Delta Q}{t\,\Delta \theta \,} $ $ =\frac{J}{sK} $ $ =\frac{J}{s}{{K}^{-1}} $ $ =W{{K}^{-1}} $