The uncertainty in the position of an electron moving with a velocity of 3 × 104 cm / sec accurate up to 0.011 % will be:

Question

The uncertainty in the position of an electron moving with a velocity of 3 × 104 cm / sec accurate up to 0.011 % will be: (A) 1.92 cm (B) 7.66 cm (C) 0.175 cm (D) 3.84 cm

Tardigrade Admin · Accepted Answer

According to Heisenberg principle Δ x=(h/4 π m Δ v) Δ x=(6.6 × 10-27 × 100/4 × 3.14 × 9.1 × 10-28 × 3 × 104 × 0.011) Δ x=0.175 cm

Q. The uncertainty in the position of an electron moving with a velocity of $3 \times 1 0^{4} c m / sec$ accurate up to $0.011%$ will be:

$1.92 c m$

$7.66 c m$

$0.175 c m$

$3.84 c m$

According to Heisenberg principle

$Δ x = \frac{h}{4 πm Δ v}$

$Δ x = \frac{6.6 \times 1 0 ^{- 27} \times 100}{4 \times 3.14 \times 9.1 \times 1 0 ^{- 28} \times 3 \times 1 0 ^{4} \times 0.011}$

$Δ x = 0.175 c m$

Q. The uncertainty in the position of an electron moving with a velocity of 3×104cm/sec accurate up to 0.011% will be:

1.92cm

7.66cm

0.175cm

3.84cm