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Chemistry
The uncertainty in the position of an electron moving with a velocity of 3 × 104 cm / sec accurate up to 0.011 % will be:
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Q. The uncertainty in the position of an electron moving with a velocity of $3 \times 10^{4} cm / sec$ accurate up to $0.011 \%$ will be:
Structure of Atom
A
$1.92 \,cm$
28%
B
$7.66 \,cm$
14%
C
$0.175 \,cm$
56%
D
$3.84 \,cm$
3%
Solution:
According to Heisenberg principle
$\Delta x=\frac{h}{4 \pi m \Delta v}$
$\Delta x=\frac{6.6 \times 10^{-27} \times 100}{4 \times 3.14 \times 9.1 \times 10^{-28} \times 3 \times 10^{4} \times 0.011}$
$\Delta x=0.175\, cm$