Question

The type of isomerism exhibited by the compound with formula $C_4{H}_{10}O$ is:

• A. Chain and position
• B. Functional and position
• C. Metamerism
• D. Chain, position, functional, and metamerism

Answer 1

Answer: (D)

D.U. in $C_4{H}_{10}O=\frac{\left(2n_C+2\right)-n_H}{2}=\frac{10-10}{2}=0$
It should be alcohol or ether
i. Alcohols and ethers are functional isomers
ii. Alcohol shows position and chain isomerism
iii. Ether shows position isomerism and metamerism
So the compound $\left(C_4{H}_{10}O\right)$ shows chain, position, functional isomerisms and metamerism