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Q.
The type of isomerism exhibited by the compound with formula $C _4 H _{10} O$ is:
Organic Chemistry – Some Basic Principles and Techniques
Solution:
D.U. in $C _4 H _{10} O =\frac{\left(2 n_{ C }+2\right)-n_{ H }}{2}=\frac{10-10}{2}=0$
It should be alcohol or ether
i. Alcohols and ethers are functional isomers
ii. Alcohol shows position and chain isomerism
iii. Ether shows position isomerism and metamerism
So the compound $\left( C _4 H _{10} O \right)$ shows chain, position, functional isomerisms and metamerism