The true statement for the graph of inequations 3x + 2y ≤ 6 and 6x + 4y ≥ 20, is

Question

The true statement for the graph of inequations 3x + 2y ≤ 6 and 6x + 4y ≥ 20, is (A) Both graphs are disjoint (B) Both do not contain origin (C) Both contain point (1, 1) (D) None of these

Tardigrade Admin · Accepted Answer

The equations, corresponding to inequalities 3x + 2y ≤ 6 and 6x + 4y ≥ 20, are 3x + 2y =6 and 6x + 4y = 20. So the lines represented by these equations are parallel. Hence the graphs are disjoint.

Q. The true statement for the graph of inequations $3 x + 2 y \leq 6$ and $6 x + 4 y \geq 20,$ is

Both graphs are disjoint

Both do not contain origin

Both contain point (1, 1)

None of these

The equations, corresponding to inequalities $3 x + 2 y \leq 6$ and $6 x + 4 y \geq 20,$ are $3 x + 2 y = 6$ and $6 x + 4 y = 20$ . So the lines represented by these equations are parallel. Hence the graphs are disjoint.

Q. The true statement for the graph of inequations 3x+2y≤6 and 6x+4y≥20, is