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  4. The true statement for the graph of inequations 3x + 2y ≤ 6 and 6x + 4y ≥ 20, is

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Q. The true statement for the graph of inequations $3x + 2y \leq 6$ and $6x + 4y \geq 20,$ is

Linear Programming

Solution:

The equations, corresponding to inequalities $3x + 2y \leq 6$ and $6x + 4y \geq 20,$ are $3x + 2y =6$ and $ 6x + 4y = 20$. So the lines represented by these equations are parallel. Hence the graphs are disjoint.

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