The transistor parameters, namely α and β of a transistor are related as

Question

The transistor parameters, namely α and β of a transistor are related as (A)  (1/α) +(1/β) = 1  (B)  (1/α) =β+ (1/β)  (C)  (1/α) - (1/β) = 0  (D)  (1/α) - (1/β) = 1

Tardigrade Admin · Accepted Answer

For common-emitter transistor β=(α/1-α) ⇒ (1-α/α)=(1/β) or (1/α)-(1/β)=1

Q. The transistor parameters, namely $α$ and $β$ of a transistor are related as

$\frac{1}{α} + \frac{1}{β} = 1$

$\frac{1}{α} = β + \frac{1}{β}$

$\frac{1}{α} - \frac{1}{β} = 0$

$\frac{1}{α} - \frac{1}{β} = 1$

For common-emitter transistor
$β = \frac{α}{1 - α}$
$\Rightarrow \frac{1 - α}{α} = \frac{1}{β}$
or $\frac{1}{α} - \frac{1}{β} = 1$

Q. The transistor parameters, namely α and β of a transistor are related as

α1​+β1​=1

α1​=β+β1​

α1​−β1​=0

α1​−β1​=1

For common-emitter transistor β=1−αα​ ⇒α1−α​=β1​ or α1​−β1​=1