Question

The transfer characteristic curve of a transistor, having input and output resistance $100\Omega$ and $100k\Omega$ respectively, is shown in the figure. The Voltage and Power gain, are respectively :

• A. $5\times 10^4,5\times 10^5$
• B. $5\times 10^4,5\times 10^6$
• C. $5\times 10^4,2.5\times 10^6$
• D. $2.5\times 10^4,2.5\times 10^6$

Answer 1

Answer: (C)

$V_{gain}=\left(\frac{\Delta I_c}{\Delta I_B}\right)\frac{R_{\text{out}}}{R_{\text{in}}}$
$=\left(\frac{5\times 10^{-3}}{100\times 10^{-6}}\right)\times 10^3$
$=\frac{1}{20}\times 10^6=5\times 10^4$
$P_{gain}=\left(\frac{\Delta I_c}{\Delta I_b}\right)\left(V_{gain}\right)$
$=\left(\frac{5\times 10^{-3}}{100\times 10^{-6}}\right)\left(5\times 10^4\right)$
$=2.5\times 10^6$