Question

The transfer characteristic curve of a transistor, having input and output resistance $100\, \Omega$ and $100 \,k\, \Omega $ respectively, is shown in the figure. The Voltage and Power gain, are respectively :

• A. $5 \times 10^4 , 5 \times 10^5$
• B. $5 \times 10^4 , 5 \times 10^6$
• C. $5 \times 10^4 , 2.5 \times 10^6$
• D. $2.5 \times 10^4 , 2.5 \times 10^6$

Answer 1

Answer: (C)

$V_{gain } =\left(\frac{\Delta I_{c}}{\Delta I_{B}}\right) \frac{R_{\text{out}}}{R_{\text{in}}} $
$ = \left(\frac{5\times10^{-3}}{100 \times10^{-6}}\right) \times10^{3} $
$ = \frac{1}{20} \times10^{6} = 5 \times10^{4} $
$ P_{gain } = \left(\frac{\Delta I_{c}}{\Delta I_{b}}\right) \left(V_{gain }\right) $
$ = \left(\frac{5\times10^{-3}}{100 \times10^{-6}} \right) \left(5\times10^{4}\right) $
$ = 2.5 \times10^{6} $