The trajectory of a projectile projected from origin is given by the equation y = x â (2x2/5) . The initial velocity of the projectile is

Question

The trajectory of a projectile projected from origin is given by the equation y = x â (2x2/5) . The initial velocity of the projectile is (A) 25 ms−1 (B) (2/5) msâ1 (C) (5/2) msâ1 (D) 5 ms−1

Tardigrade Admin · Accepted Answer

y=x -(2x2/5) tan θ=1 θ=45° (g/2u 2 cos 2θ)=(2/5) (10/2u2 (1)2)=(2/5) u2=(50/2)=25 u=5 ms-1

Q. The trajectory of a projectile projected from origin is given by the equation y = x − $\frac{2 x ^{2}}{5}$ . The initial velocity of the projectile is

$25 m s^{- 1}$

$\frac{2}{5} m s^{- 1}$

$\frac{5}{2} m s^{- 1}$

$5 m s^{- 1}$

$y = x - \frac{2 x ^{2}}{5}$
$t an θ = 1$
$θ = 4 5^{\circ}$
$\frac{g}{2 u ^{2} co s ^{2} θ} = \frac{2}{5}$
$\frac{10}{2 u ^{2} \frac{1}{2}} = \frac{2}{5}$
$u^{2} = \frac{50}{2} = 25$
$u = 5 m s^{- 1}$

Q. The trajectory of a projectile projected from origin is given by the equation y = x − 52x2​ . The initial velocity of the projectile is

25ms−1

52​ms−1

25​ms−1

5ms−1