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Q. The trajectory of a projectile projected from origin is given by the equation y = x − $\frac{2x^2}{5}$ . The initial velocity of the projectile is

KCETKCET 2019Motion in a Plane

Solution:

$y=x -\frac{2x^{2}}{5}$
$tan \, \theta=1$
$\theta=45^{\circ}$
$\frac{g}{2u ^{2} cos ^{2}\theta}=\frac{2}{5}$
$\frac{10}{2u^{2} \frac{1}{2}}=\frac{2}{5}$
$u^{2}=\frac{50}{2}=25$
$u=5 \, ms^{-1}$