The total pressure of a mixture of non-reacting gases X (0.6 g ) and Y (0.45 g ) in a vessel is 740 mm of Hg. The partial pressure of the gas X is mm of Hg. (Nearest Integer) (Given: molar mass X =20 and Y =45 g mol -1 )

Question

The total pressure of a mixture of non-reacting gases X (0.6 g ) and Y (0.45 g ) in a vessel is 740 mm of Hg. The partial pressure of the gas X is mm of Hg. (Nearest Integer) (Given: molar mass X =20 and Y =45 g mol -1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P x = chi X P T =((0.6/20)/(0.6)20+(0.45)45 × 740 P / X )=555 mm Hg

Q. The total pressure of a mixture of non-reacting gases $X (0.6 g)$ and $Y (0.45 g)$ in a vessel is $740 mm$ of $H g$ . The partial pressure of the gas $X$ is ____ $mm$ of $H g$ . (Nearest Integer)
(Given : molar mass $X = 20$ and $Y = 45 g m o l^{- 1}$ )

$P_{x} = χ_{X} P_{T}$
$= \frac{\frac{0.6}{20}}{\frac{0.6}{20} + \frac{0.45}{45}} \times 740$
$P_{X} = 555 mm H g$

Q. The total pressure of a mixture of non-reacting gases X(0.6g) and Y(0.45g) in a vessel is 740mm of Hg. The partial pressure of the gas X is ____mm of Hg. (Nearest Integer) (Given : molar mass X=20 and Y=45gmol−1 )

Px​=χX​PT​ =200.6​+450.45​200.6​​×740 PX​=555mmHg

Q. The total pressure of a mixture of non-reacting gases $X (0.6 g)$ and $Y (0.45 g)$ in a vessel is $740 mm$ of $H g$ . The partial pressure of the gas $X$ is ____ $mm$ of $H g$ . (Nearest Integer)
(Given : molar mass $X = 20$ and $Y = 45 g m o l^{- 1}$ )

$P_{x} = χ_{X} P_{T}$
$= \frac{\frac{0.6}{20}}{\frac{0.6}{20} + \frac{0.45}{45}} \times 740$
$P_{X} = 555 mm H g$