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Q. The total pressure of a mixture of non-reacting gases $X (0.6 \,g )$ and $Y (0.45 \, g )$ in a vessel is $740\, mm$ of $Hg$. The partial pressure of the gas $X$ is ____$mm$ of $Hg$. (Nearest Integer)
(Given : molar mass $X =20$ and $Y =45 \, g \, mol ^{-1}$ )

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Solution:

$P _{ x }=\chi_{ X } P _{ T } $
$ =\frac{\frac{0.6}{20}}{\frac{0.6}{20}+\frac{0.45}{45}} \times 740 $
$ P _{ X }=555 \,mm \,Hg$