The total number of protons in 10 g of calcium carbonate is (N0=6.023× 1023) :

Question

The total number of protons in 10 g of calcium carbonate is (N0=6.023× 1023) : (A)  3.01× 1024 (B)  4.06× 1024 (C)  2.01× 1024 (D)  3.02× 1024

Tardigrade Admin · Accepted Answer

We know that protons in 1 molec CaCO 3 = atomic number of calcium +atomic number of carbon +3(atomic number of oxygen) =20+6+3 (8) =50 moles ∴ proton in 10 g CaCO 3 =(10 × 50/100) × 6.02 × 1023 =3.01 × 1024

Q. The total number of protons in $10 g$ of calcium carbonate is $(N_{0} = 6.023 \times 1 0^{23})$ :

$3.01 \times 1 0^{24}$

$4.06 \times 1 0^{24}$

$2.01 \times 1 0^{24}$

$3.02 \times 1 0^{24}$

We know that protons in 1 molec $C a C O_{3}$
$=$ atomic number of calcium +atomic number of carbon
+3(atomic number of oxygen)
$= 20 + 6 + 3 (8)$
$= 50$ moles
$∴$ proton in $10 g$
$C a C O_{3} = \frac{10 \times 50}{100} \times 6.02 \times 1 0^{23}$
$= 3.01 \times 1 0^{24}$

Q. The total number of protons in 10g of calcium carbonate is (N0​=6.023×1023) :

3.01×1024

4.06×1024

2.01×1024

3.02×1024