Question

The total number of protons in $ 10\,g$ of calcium carbonate is $ (N_{0}=6.023\times 10^{23})$ :

• A. $ 3.01\times 10^{24}$
• B. $ 4.06\times 10^{24}$
• C. $ 2.01\times 10^{24}$
• D. $ 3.02\times 10^{24}$

Answer 1

Answer: (A)

We know that protons in 1 molec $CaCO _{3}$
$=$ atomic number of calcium +atomic number of carbon
+3(atomic number of oxygen)
$=20+6+3 (8)$
$=50$ moles
$\therefore $ proton in $10\, g$
$CaCO _{3} =\frac{10 \times 50}{100} \times 6.02 \times 10^{23}$
$=3.01 \times 10^{24}$