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Tardigrade
Question
Chemistry
The total number of possible isomers for the complex compound [ Cu II ( NH 3)4][ Pt II Cl 4] are
Q. The total number of possible isomers for the complex compound
[
C
u
II
(
N
H
3
)
4
]
[
P
t
II
C
l
4
]
are
3935
208
AIPMT
AIPMT 1998
Coordination Compounds
Report Error
A
5
8%
B
6
21%
C
3
17%
D
4
54%
Solution:
Total isomers of the given complex are four. These are
(i)
[
C
u
(
N
H
3
)
4
]
[
PtC
l
4
]
(ii)
[
C
u
(
N
H
3
)
3
Cl
]
[
Pt
(
N
H
3
)
C
l
3
]
(iii)
[
Pt
(
N
H
3
)
3
Cl
]
[
C
u
(
N
H
3
)
C
l
3
]
(iv)
[
Pt
(
N
H
3
)
4
]
[
C
u
C
l
4
]