Question

The total number of possible isomers for the complex compound $\left[ Cu ^{ II }\left( NH _{3}\right)_{4}\right]\left[ Pt ^{ II } Cl _{4}\right]$ are

• A. 5
• B. 6
• C. 3
• D. 4

Answer 1

Answer: (D)

Total isomers of the given complex are four. These are
(i) $\left[ Cu \left( NH _{3}\right)_{4}\right]\left[ PtCl _{4}\right]$
(ii) $\left[ Cu \left( NH _{3}\right)_{3} Cl \right]\left[ Pt \left( NH _{3}\right) Cl _{3}\right]$
(iii) $\left[ Pt \left( NH _{3}\right)_{3} Cl \right]\left[ Cu \left( NH _{3}\right) Cl _{3}\right]$
(iv) $\left[ Pt \left( NH _{3}\right)_{4}\right]\left[ CuCl _{4}\right]$