The total number of possible isomers for square-planar [Pt(Cl)(NO2)(NO3)(SCN)]2- is :

Question

The total number of possible isomers for square-planar [Pt(Cl)(NO2)(NO3)(SCN)]2- is : (A) 8 (B) 12 (C) 16 (D) 24

Tardigrade Admin · Accepted Answer

Total number of possible isomers for square planar [Pt(Cl)(NO2)(NO3)(SCN)]2-. MABCD complex: geometrical isomers NO2 and SCN are ambidentate ligand total isomers =4×3=12

Q. The total number of possible isomers for square-planar $[Pt (Cl) (N O_{2}) (N O_{3}) (SCN)]^{2 -}$ is :

8

12

16

24

Total number of possible isomers for square planar $[Pt (Cl) (N O_{2}) (N O_{3}) (SCN)]^{2 -}$ .

$M A BC D$ complex : geometrical isomers

$N O_{2}$ and $SCN$ are ambidentate ligand

total isomers $= 4 \times 3 = 12$

Q. The total number of possible isomers for square-planar [Pt(Cl)(NO2​)(NO3​)(SCN)]2− is :

8

12

16

24

Total number of possible isomers for square planar [Pt(Cl)(NO2​)(NO3​)(SCN)]2−. MABCD complex : geometrical isomers NO2​ and SCN are ambidentate ligand total isomers =4×3=12

Q. The total number of possible isomers for square-planar $[Pt (Cl) (N O_{2}) (N O_{3}) (SCN)]^{2 -}$ is :

Total number of possible isomers for square planar $[Pt (Cl) (N O_{2}) (N O_{3}) (SCN)]^{2 -}$ .

$M A BC D$ complex : geometrical isomers

$N O_{2}$ and $SCN$ are ambidentate ligand

total isomers $= 4 \times 3 = 12$