Q. The total number of possible isomers for square-planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$ is :
Solution:
Total number of possible isomers for square planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$.
$MABCD$ complex : geometrical isomers
$NO_2$ and $SCN$ are ambidentate ligand
total isomers $=4\times3=12$
