The total energy of electron in the ground state of hydrogen atom is -13.6 eV . The kinetic energy of an electron in the first excited state is

Question

The total energy of electron in the ground state of hydrogen atom is -13.6 eV . The kinetic energy of an electron in the first excited state is (A) 6.8cV (B) 13.6eV (C) 1.7eV (D) 3.4eV

Tardigrade Admin · Accepted Answer

Total energy of electron in ground state E =-13.6 eV Total energy in the first excited state E1=(-13.6/22)=-3.4 eV Kinetic energy of electron in first excited state K 1=| E 1|=3.4 eV

Q. The total energy of electron in the ground state of hydrogen atom is $- 13.6 e V$ . The kinetic energy of an electron in the first excited state is

6.8cV

13.6eV

1.7eV

3.4eV

Total energy of electron in ground state $E = - 13.6 e V$
Total energy in the first excited state $E_{1} = \frac{- 13.6}{2 ^{2}} = - 3.4 e V$
Kinetic energy of electron in first excited state $K_{1} = ∣ E_{1} ∣ = 3.4 e V$

Q. The total energy of electron in the ground state of hydrogen atom is −13.6eV . The kinetic energy of an electron in the first excited state is