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  4. The total energy of electron in the ground state of hydrogen atom is -13.6 eV . The kinetic energy of an electron in the first excited state is

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Q. The total energy of electron in the ground state of hydrogen atom is $-13.6\, eV$ . The kinetic energy of an electron in the first excited state is

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Solution:

Total energy of electron in ground state $E =-13.6 eV$
Total energy in the first excited state $E_{1}=\frac{-13.6}{2^{2}}=-3.4 eV$
Kinetic energy of electron in first excited state $K _{1}=\left| E _{1}\right|=3.4 eV$