The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively

Question

The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively (A) 1.51 eV, -3.02 eV (B) -1.51 eV, 3.02 eV (C) 3.02 eV, -1.51 eV (D) -3.02 eV, 1.51 eV

Tardigrade Admin · Accepted Answer

In the second excited state, Total energy, E = -1.51 eV Kinetic energy, K = -E = -(-1.51 eV) = 1.51 eV Potential energy, U = 2E = 2(-1.51 eV) = -3.02 eV

Q. The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively

1.51 eV, -3.02 eV

-1.51 eV, 3.02 eV

3.02 eV, -1.51 eV

-3.02 eV, 1.51 eV

In the second excited state,
Total energy, $E = - 1.51 e V$
Kinetic energy, $K = - E = - (- 1.51 e V) = 1.51 e V$
Potential energy, $U = 2 E = 2 (- 1.51 e V) = - 3.02 e V$

Q. The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively

1.51 eV, -3.02 eV

-1.51 eV, 3.02 eV

3.02 eV, -1.51 eV

-3.02 eV, 1.51 eV

In the second excited state, Total energy, E=−1.51eV Kinetic energy, K=−E=−(−1.51eV)=1.51eV Potential energy, U=2E=2(−1.51eV)=−3.02eV

In the second excited state,
Total energy, $E = - 1.51 e V$
Kinetic energy, $K = - E = - (- 1.51 e V) = 1.51 e V$
Potential energy, $U = 2 E = 2 (- 1.51 e V) = - 3.02 e V$