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  4. The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively

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Q. The total energy of an electron in the second excited state of the hydrogen atom is -1.51 eV. The kinetic and potential energies of the electron in this state are respectively

Atoms

Solution:

In the second excited state,
Total energy, $E = -1.51\, eV$
Kinetic energy, $K = -E = -(-1.51 eV) = 1.51 \,eV$
Potential energy, $U = 2E = 2(-1.51 eV) = -3.02 \,eV$