The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be: (velocity of light in air .=3 × 108 m / s )

Question

The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be: (velocity of light in air .=3 × 108 m / s ) (A)  8× 10-11s  (B)  2× 10-11s  (C)  8× 10-8s  (D)  2× 10-8s

Tardigrade Admin · Accepted Answer

Time taken by light t =(μ d/c) =(1.5 × 4 × 10-3/3 × 108)=2 × 10-11 s

Q. The time taken by light to pass through $4 mm$ thick glass slab of refractive index $1.5$ will be : (velocity of light in air $= 3 \times 1 0^{8} m / s)$

$8 \times 1 0^{- 11} s$

$2 \times 1 0^{- 11} s$

$8 \times 10^{- 8} s$

$2 \times 1 0^{- 8} s$

Time taken by light
$t = \frac{μ d}{c}$
$= \frac{1.5 \times 4 \times 1 0 ^{- 3}}{3 \times 1 0 ^{8}} = 2 \times 1 0^{- 11} s$

Q. The time taken by light to pass through 4mm thick glass slab of refractive index 1.5 will be : (velocity of light in air =3×108m/s)

8×10−11s

2×10−11s

8×10−8s

2×10−8s