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Q. The time taken by light to pass through $4\, mm$ thick glass slab of refractive index $1.5$ will be : (velocity of light in air $\left.=3 \times 10^{8} m / s \right)$

JIPMERJIPMER 2006

Solution:

Time taken by light
$t =\frac{\mu d}{c}$
$=\frac{1.5 \times 4 \times 10^{-3}}{3 \times 10^{8}}=2 \times 10^{-11} s$