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Physics
The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be: (velocity of light in air .=3 × 108 m / s )
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Q. The time taken by light to pass through $4\, mm$ thick glass slab of refractive index $1.5$ will be : (velocity of light in air $\left.=3 \times 10^{8} m / s \right)$
JIPMER
JIPMER 2006
A
$ 8\times 10^{-11}s $
B
$ 2\times 10^{-11}s $
C
$ 8\times {{10}^{-8}}s $
D
$ 2\times 10^{-8}s $
Solution:
Time taken by light
$t =\frac{\mu d}{c}$
$=\frac{1.5 \times 4 \times 10^{-3}}{3 \times 10^{8}}=2 \times 10^{-11} s$