Question

The time period of a simple pendulum of length $9.8m$ is

• A. 0.159 s
• B. 3.14 s
• C. 6.5 s
• D. 6.28 s

Answer 1

Answer: (D)

Time period $T=2\pi \sqrt{\frac{l}{g}}$
Given, $g=9.8m/s^2,l=9.8m$
$T=2\pi \sqrt{\frac{9.8}{9.8}}=2\pi =2\times 3.14=6.28s$