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  4. The time period of a simple pendulum of length 9.8 m is

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Q. The time period of a simple pendulum of length $ 9.8\,m $ is

J & K CETJ & K CET 2013Oscillations

Solution:

Time period $T=2 \pi \sqrt{\frac{l}{g}}$
Given, $g=9.8\, m / s ^{2}, l=9.8\, m$
$T=2 \pi \sqrt{\frac{9.8}{9.8}}=2 \pi=2 \times 3.14=6.28\, s$