The time of revolution of an electron around a nucleus of charge Ze in nth Bohrs orbit is directly proportional to

Question

The time of revolution of an electron around a nucleus of charge Ze in nth Bohrs orbit is directly proportional to (A)  n  (B)  (n3/Z2)  (C)  (n2/Z)  (D)  (Z/n)

Tardigrade Admin · Accepted Answer

r propto (n2/Z) and v propto (Z/n2) Time period of revolution of an electron around the nucleus of charge Ze is T=(2 π r/v)=2 π (n2/Z) ⋅ (n/Z) ⇒ T propto (n3/Z2)

Q. The time of revolution of an electron around a nucleus of charge $Z e$ in nth Bohrs orbit is directly proportional to

$n$

$\frac{n ^{3}}{Z ^{2}}$

$\frac{n ^{2}}{Z}$

$\frac{Z}{n}$

$r \propto \frac{n ^{2}}{Z}$ and $v \propto \frac{Z}{n ^{2}}$
Time period of revolution of an electron around the nucleus of charge $Z e$ is
$T = \frac{2 π r}{v} = 2 π \frac{n ^{2}}{Z} \cdot \frac{n}{Z}$
$\Rightarrow T \propto \frac{n ^{3}}{Z ^{2}}$

Q. The time of revolution of an electron around a nucleus of charge Ze in nth Bohrs orbit is directly proportional to

n

Z2n3​

Zn2​

nZ​

r∝Zn2​ and v∝n2Z​ Time period of revolution of an electron around the nucleus of charge Ze is T=v2πr​=2πZn2​⋅Zn​ ⇒T∝Z2n3​

Q. The time of revolution of an electron around a nucleus of charge $Z e$ in nth Bohrs orbit is directly proportional to

$n$

$\frac{n ^{3}}{Z ^{2}}$

$\frac{n ^{2}}{Z}$

$\frac{Z}{n}$

$r \propto \frac{n ^{2}}{Z}$ and $v \propto \frac{Z}{n ^{2}}$
Time period of revolution of an electron around the nucleus of charge $Z e$ is
$T = \frac{2 π r}{v} = 2 π \frac{n ^{2}}{Z} \cdot \frac{n}{Z}$
$\Rightarrow T \propto \frac{n ^{3}}{Z ^{2}}$