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Q. The time of revolution of an electron around a nucleus of charge $Ze$ in nth Bohrs orbit is directly proportional to

ManipalManipal 2011Atoms

Solution:

$r \propto \frac{n^{2}}{Z}$ and $v \propto \frac{Z}{n^{2}}$
Time period of revolution of an electron around the nucleus of charge $Ze$ is
$T=\frac{2 \pi r}{v}=2 \pi \frac{n^{2}}{Z} \cdot \frac{n}{Z}$
$\Rightarrow T \propto \frac{n^{3}}{Z^{2}}$