The three initial and final positions of a man on the x-axis are given as (i) (-3 m, 7 m) (ii) (7 m, -3 m) (iii) (-7 m, 3 m) Which pair gives the negative displacement ?

Question

The three initial and final positions of a man on the x-axis are given as (i) (-3 m, 7 m) (ii) (7 m, -3 m) (iii) (-7 m, 3 m) Which pair gives the negative displacement ? (A) (i) (B) (ii) (C) (iii) (D) (i) and (iii)

Tardigrade Admin · Accepted Answer

Displacement = Final position - Initial position Δ x=x2-x1 Then, (i) Δ x = 7 m - (-3 m) = 10 m (ii) Δ x = -3 m - 7 m = - 10 m (iii) Δ x = 3 m - (-7 m) = 10 m

Q. The three initial and final positions of a man on the $x$ -axis are given as
(i) $(- 3 m, 7 m)$
(ii) $(7 m, - 3 m)$
(iii) $(- 7 m, 3 m)$
Which pair gives the negative displacement ?

(i)

(ii)

(iii)

(i) and (iii)

Displacement $=$ Final position $-$ Initial position
$Δ x = x_{2} - x_{1}$
Then,
(i) $Δ x = 7 m - (- 3 m) = 10 m$
(ii) $Δ x = - 3 m - 7 m = - 10 m$
(iii) $Δ x = 3 m - (- 7 m) = 10 m$

Q. The three initial and final positions of a man on the x-axis are given as (i) (−3m,7m) (ii) (7m,−3m) (iii) (−7m,3m) Which pair gives the negative displacement ?

(i)

(ii)

(iii)

(i) and (iii)

Displacement = Final position − Initial position Δx=x2​−x1​ Then, (i) Δx=7m−(−3m)=10m (ii) Δx=−3m−7m=−10m (iii) Δx=3m−(−7m)=10m

Q. The three initial and final positions of a man on the $x$ -axis are given as
(i) $(- 3 m, 7 m)$
(ii) $(7 m, - 3 m)$
(iii) $(- 7 m, 3 m)$
Which pair gives the negative displacement ?

Displacement $=$ Final position $-$ Initial position
$Δ x = x_{2} - x_{1}$
Then,
(i) $Δ x = 7 m - (- 3 m) = 10 m$
(ii) $Δ x = - 3 m - 7 m = - 10 m$
(iii) $Δ x = 3 m - (- 7 m) = 10 m$