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Q. The three initial and final positions of a man on the $x$-axis are given as
(i) $(-3 \,m, 7 \,m)$
(ii) $(7 \,m, -3 \,m)$
(iii) $(-7\, m, 3 \,m)$
Which pair gives the negative displacement ?

Motion in a Straight Line

Solution:

Displacement $=$ Final position $-$ Initial position
$\Delta x=x_{2}-x_{1}$
Then,
(i) $\Delta x = 7 \,m - (-3\, m) = 10\, m$
(ii) $\Delta x = -3 \,m - 7 \,m = - 10 \,m$
(iii) $\Delta x = 3\, m - (-7 \,m) = 10 \,m$