The terminal velocity v of a spherical ball of lead of radius R falling through a viscous liquid varies with R such that

Question

The terminal velocity v of a spherical ball of lead of radius R falling through a viscous liquid varies with R such that (A) (v/R)= constant (B) vR= constant (C) v= constant (D) (v/R2)= constant

Tardigrade Admin · Accepted Answer

The terminal velocity is given by: v=(2 r2 (. ρ - (ρ )0 .) g/9 η) Or (v/r2)=(2 (. ρ - (ρ )0 .) g/9 η)= constant

Q. The terminal velocity $v$ of a spherical ball of lead of radius $R$ falling through a viscous liquid varies with $R$ such that

$\frac{v}{R} =$ constant

$v R =$ constant

$v =$ constant

$\frac{v}{R ^{2}} =$ constant

The terminal velocity is given by :
$v = \frac{2 r ^{2} ( ρ - ( ρ ) _{0} ) g}{9 η}$
Or $\frac{v}{r ^{2}} = \frac{2 ( ρ - ( ρ ) _{0} ) g}{9 η} =$ constant

Q. The terminal velocity v of a spherical ball of lead of radius R falling through a viscous liquid varies with R such that

Rv​= constant

vR= constant

v= constant

R2v​= constant