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Q. The terminal velocity $v$ of a spherical ball of lead of radius $R$ falling through a viscous liquid varies with $R$ such that

NTA AbhyasNTA Abhyas 2020

Solution:

The terminal velocity is given by :
$v=\frac{2 r^{2} \left(\right. \rho - \left(\rho \right)_{0} \left.\right) g}{9 \eta}$
Or $\frac{v}{r^{2}}=\frac{2 \left(\right. \rho - \left(\rho \right)_{0} \left.\right) g}{9 \eta}=$ constant