The tension in the string of a simple pendulum is

Question

The tension in the string of a simple pendulum is (A) constant (B) maximum in the extreme position (C) zero in the mean position (D) none of these

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7057a34497529408979c6f459de27944-.png" /> Along the radial direction, T-mg cos θ=(m v2/l) or T=(m v2/l)+mg cos θ T text mean position is highest as v is maximum there and cos 0=1 T text exteme position is mg cos θ as v is zero. Hence the correct choice is (d)

Q. The tension in the string of a simple pendulum is

constant

maximum in the extreme position

zero in the mean position

none of these

Along the radial direction,
$T - m g cos θ = \frac{m v ^{2}}{l}$ or $T = \frac{m v ^{2}}{l} + m g cos θ$
$T_{mean}$ position is highest as $v$ is maximum there and $cos 0 = 1$
$T_{exteme}$ position is $m g cos θ$ as $v$ is zero. Hence the correct choice is (d)

Q. The tension in the string of a simple pendulum is

constant

maximum in the extreme position

zero in the mean position

none of these

Along the radial direction, T−mgcosθ=lmv2​ or T=lmv2​+mgcosθ Tmean ​ position is highest as v is maximum there and cos0=1 Texteme ​ position is mgcosθ as v is zero. Hence the correct choice is (d)

Along the radial direction,
$T - m g cos θ = \frac{m v ^{2}}{l}$ or $T = \frac{m v ^{2}}{l} + m g cos θ$
$T_{mean}$ position is highest as $v$ is maximum there and $cos 0 = 1$
$T_{exteme}$ position is $m g cos θ$ as $v$ is zero. Hence the correct choice is (d)