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Q.
The tension in the string of a simple pendulum is
Oscillations
Solution:
Along the radial direction,
$T-mg\, \cos\, \theta=\frac{m v^{2}}{l}$ or $T=\frac{m v^{2}}{l}+mg \,\cos\, \theta$
$T_{\text {mean }}$ position is highest as $v$ is maximum there and $\cos 0=1$
$T_{\text {exteme }}$ position is $mg \cos \theta$ as $v$ is zero. Hence the correct choice is (d)
