The temperature of two bodies A and B are respectively, 727°C and 327°C. The ratio HA: HB of the rates of heat radiated by them is

Question

The temperature of two bodies A and B are respectively, 727°C and 327°C. The ratio HA: HB of the rates of heat radiated by them is (A) 727: 327 (B) 5: 3 (C) 25: 9 (D) 625: 81

Tardigrade Admin · Accepted Answer

(HA/HB) =((727 + 273)4/(327 +273)4) = ((1000/600))4 = (5 ×5×5×5/3×3×3×3) = (625/81)

Q. The temperature of two bodies $A$ and $B$ are respectively, $727° C$ and $327° C$ . The ratio $H_{A} : H_{B}$ of the rates of heat radiated by them is

727 : 327

5 : 3

25 : 9

625 : 81

$\frac{H _{A}}{H _{B}} = \frac{( 727 + 273 ) ^{4}}{( 327 + 273 ) ^{4}}$
$= (\frac{1000}{600})^{4} = \frac{5 \times 5 \times 5 \times 5}{3 \times 3 \times 3 \times 3} = \frac{625}{81}$

Q. The temperature of two bodies A and B are respectively, 727°C and 327°C. The ratio HA​:HB​ of the rates of heat radiated by them is