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Physics
The temperature of two bodies A and B are respectively, 727°C and 327°C. The ratio HA: HB of the rates of heat radiated by them is
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Q. The temperature of two bodies $A$ and $B$ are respectively, $727°C$ and $327°C$. The ratio $H_A : H_B$ of the rates of heat radiated by them is
JIPMER
JIPMER 2013
Thermal Properties of Matter
A
727 : 327
29%
B
5 : 3
20%
C
25 : 9
18%
D
625 : 81
33%
Solution:
$\frac{H_{A}}{H_{B}} =\frac{\left(727 + 273\right)^{4}}{\left(327 +273\right)^{4}}$
$= \left(\frac{1000}{600}\right)^{4} = \frac{5 \times5\times5\times5}{3\times3\times3\times3} = \frac{625}{81}$