The temperature of a substance increases by 27° C. On the Kelvin scale this increase is equal to

Question

The temperature of a substance increases by 27° C. On the Kelvin scale this increase is equal to (A) 300 K (B) 2.46 K (C) 27 K (D) 7 K

Tardigrade Admin · Accepted Answer

Suppose, C = temperature at Celsius scale K = temperature at Kelvin scale Now, K = C +273 But the change in the temperature will be same by cancelling the 273° factor. So, Δ° C =Δ° K

Q. The temperature of a substance increases by $2 7^{\circ} C$ . On the Kelvin scale this increase is equal to

300 K

2.46 K

27 K

7 K

Suppose, $C =$ temperature at Celsius scale
$K =$ temperature at Kelvin scale
Now,
$< b r / > K = C + 273 < b r / >$
But the change in the temperature will be same by cancelling the $27 3^{\circ}$ factor. So, $Δ^{\circ} C = Δ^{\circ} K$

Q. The temperature of a substance increases by 27∘C. On the Kelvin scale this increase is equal to

300 K

2.46 K

27 K

7 K

Suppose, C= temperature at Celsius scale K= temperature at Kelvin scale Now, <br/>K=C+273<br/> But the change in the temperature will be same by cancelling the 273∘ factor. So, Δ∘C=Δ∘K

Q. The temperature of a substance increases by $2 7^{\circ} C$ . On the Kelvin scale this increase is equal to

Suppose, $C =$ temperature at Celsius scale
$K =$ temperature at Kelvin scale
Now,
$< b r / > K = C + 273 < b r / >$
But the change in the temperature will be same by cancelling the $27 3^{\circ}$ factor. So, $Δ^{\circ} C = Δ^{\circ} K$