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Tardigrade
Question
Chemistry
The temperature of 32°C is equivalent to
Q. The temperature of
3
2
∘
C
is equivalent to
2000
187
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A
89.
6
∘
F
B
85.
6
∘
F
C
7
0
∘
F
D
6
9
∘
F
Solution:
The temperature of
∘
F
and
∘
C
are related to each other by the following relationship:
∘
F
=
5
9
(
∘
C
)
+
32
∘
F
=
5
9
×
32
+
32
=
57.6
+
32
∘
F
=
89.6
The temperature of
3
2
∘
C
is equivalent to
89.
6
∘
F
.