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Chemistry
The temperature of 32°C is equivalent to
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Q. The temperature of $32^{\circ}C$ is equivalent to
MHT CET
MHT CET 2019
A
$89.6^{\circ}F$
B
$85.6^{\circ}F$
C
$70^{\circ}F$
D
$69^{\circ}F$
Solution:
The temperature of ${ }^{\circ} F$ and ${ }^{\circ} C$ are related to each other by the following relationship:
$^{\circ} F =\frac{9}{5}\left({ }^{\circ} C \right)+32$
${ }^{\circ} F =\frac{9 \times 32}{5}+32= 57.6+32$
${ }^{\circ} F =89.6$
The temperature of $32^{\circ} C$ is equivalent to $89.6^{\circ} F$.