Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The temperature of $32^{\circ}C$ is equivalent to

MHT CETMHT CET 2019

Solution:

The temperature of ${ }^{\circ} F$ and ${ }^{\circ} C$ are related to each other by the following relationship:

$^{\circ} F =\frac{9}{5}\left({ }^{\circ} C \right)+32$

${ }^{\circ} F =\frac{9 \times 32}{5}+32= 57.6+32$

${ }^{\circ} F =89.6$

The temperature of $32^{\circ} C$ is equivalent to $89.6^{\circ} F$.