Question

The temperature at which the speed of sound becomes double as was at $27^{\circ }C$ is

• A. $273^{\circ }C$
• B. $0^{\circ }C$
• C. $927^{\circ }C$
• D. $1027^{\circ }C$

Answer 1

Answer: (C)

velocity of sound $v\propto \sqrt{T}$
$\therefore \frac{v}{2v}=\frac{\sqrt{273+27}}{\sqrt{T}}$
or $T=1200K=972^{\circ }C$