The TV signals have a bandwidth of 3.7 MHz. The number of TV channels that can be accommodated with a band of 3700 GHz is

Question

The TV signals have a bandwidth of 3.7 MHz. The number of TV channels that can be accommodated with a band of 3700 GHz is (A) 104 (B) 105 (C) 106 (D) 107

Tardigrade Admin · Accepted Answer

Here, Bandwidth of each channel= 3.7 MHz = 3.7 × 106 Hz Total bandwidth = 3700 GHz= 3700 × 109 Hz Number of TV channels accomodated = (Total bandwidth/Bandwidth per channel)= (3700 × 109/3.7 × 106) = 106

Q. The $T V$ signals have a bandwidth of $3.7 M Hz$ . The number of $T V$ channels that can be accommodated with a band of $3700 G Hz$ is

$1 0^{4}$

$1 0^{5}$

$1 0^{6}$

$1 0^{7}$

Here,
Bandwidth of each channel= $3.7 M Hz$
$= 3.7 \times 1 0^{6} Hz$
Total bandwidth $= 3700 G Hz = 3700 \times 1 0^{9} Hz$
Number of TV channels accomodated
$= \frac{T o t a l ban d w i d t h}{B an d w i d t h p er c hann e l} = \frac{3700 \times 1 0 ^{9}}{3.7 \times 1 0 ^{6}} = 1 0^{6}$

Q. The TV signals have a bandwidth of 3.7MHz. The number of TV channels that can be accommodated with a band of 3700GHz is

104

105

106

107