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Physics
The TV signals have a bandwidth of 3.7 MHz. The number of TV channels that can be accommodated with a band of 3700 GHz is
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Q. The $TV$ signals have a bandwidth of $3.7\, MHz$. The number of $TV$ channels that can be accommodated with a band of $3700 \,GHz$ is
COMEDK
COMEDK 2014
Communication Systems
A
$10^4$
22%
B
$10^5$
27%
C
$10^6$
43%
D
$10^7$
8%
Solution:
Here,
Bandwidth of each channel= $3.7 MHz$
$ = 3.7 \times 10^6 \, Hz $
Total bandwidth $= 3700 \, GHz= 3700 \times 10^9 \, Hz$
Number of TV channels accomodated
$ = \frac{Total \, bandwidth}{Bandwidth\, per\, channel}= \frac{3700 \times 10^9}{3.7 \times 10^6} = 10^6$