The symmetric part of the matrix A =[ 1&2 &4 6&8& 2 2&-2&7 ] is

Question

The symmetric part of the matrix A =[ 1&2 &4 6&8& 2 2&-2&7 ] is (A) [ 1&4 &3 2&8& 0 3&0&7 ]  (B) [ 1&4 &3 4&8& 0 3&0&7 ]  (C) [ 0&-2 &-1 -2&0& -2 -1&-2&0 ]  (D) [ 0&-2 &1 2&0& 2 -1&2&0 ]

Tardigrade Admin · Accepted Answer

Given, matrix A= [1 2 4 6 8 2 2 -2 7] ∴ Symmetric part of A=(1/2)[A+A'] =(1/2) [1 2 4 6 8 2 2 -2 7]+ [1 6 2 2 8 -2 4 2 7] =(1/2) [2 8 6 8 16 0 6 0 14] = [1 4 3 4 8 0 3 0 7]

Q. The symmetric part of the matrix $A = ⎣ ⎡ 162 28 - 2 427 ⎦ ⎤$ is

$⎣ ⎡ 123480307 ⎦ ⎤$

$⎣ ⎡ 143480307 ⎦ ⎤$

$⎣ ⎡ 0 - 2 - 1 - 2 0 - 2 - 1 - 2 0 ⎦ ⎤$

$⎣ ⎡ 02 - 1 - 2 02 120 ⎦ ⎤$

Q. The symmetric part of the matrix A=⎣⎡​162​28−2​427​⎦⎤​ is

⎣⎡​123​480​307​⎦⎤​

⎣⎡​143​480​307​⎦⎤​

⎣⎡​0−2−1​−20−2​−1−20​⎦⎤​

⎣⎡​02−1​−202​120​⎦⎤​

Q. The symmetric part of the matrix $A = ⎣ ⎡ 162 28 - 2 427 ⎦ ⎤$ is

$⎣ ⎡ 123480307 ⎦ ⎤$

$⎣ ⎡ 143480307 ⎦ ⎤$

$⎣ ⎡ 0 - 2 - 1 - 2 0 - 2 - 1 - 2 0 ⎦ ⎤$

$⎣ ⎡ 02 - 1 - 2 02 120 ⎦ ⎤$