The sum of the number of lone pairs of electrons on each central atom in the following species is [.TeBr6].2 -,[.BrF2].+ and [.XeF3].- (Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

Question

The sum of the number of lone pairs of electrons on each central atom in the following species is [.TeBr6].2 -,[.BrF2].+ and [.XeF3].- (Atomic number: F = 9, Br = 35, Te = 52, Xe = 54) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Species Lone pair on central atom TeBr2 - 1 BrF2+ 2 XeF3- 3 Total number of lone pair = 6.

Species	Lone pair on central atom
$T e B r^{2 -}$	1
$B r F_{2}^{+}$	2
$X e F_{3}^{-}$	3

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is

$[T e B r_{6}]^{2 -}, [B r F_{2}]^{+}$ and $[X e F_{3}]^{-}$

(Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

Species Lone pair on central atom

$T e B r^{2 -}$ 1

$B r F_{2}^{+}$ 2

$X e F_{3}^{-}$ 3

Total number of lone pair = 6.

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr6​]2−,[BrF2​]+ and [XeF3​]− (Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

Species Lone pair on central atom TeBr2− 1 BrF2+​ 2 XeF3−​ 3 Total number of lone pair = 6.

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is

$[T e B r_{6}]^{2 -}, [B r F_{2}]^{+}$ and $[X e F_{3}]^{-}$

(Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

Species Lone pair on central atom

$T e B r^{2 -}$ 1

$B r F_{2}^{+}$ 2

$X e F_{3}^{-}$ 3

Total number of lone pair = 6.