Q.
The sum of the number of lone pairs of electrons on each central atom in the following species is
$\left[\right.TeBr_{6}\left]\right.^{2 -},\left[\right.BrF_{2}\left]\right.^{+}$ and $\left[\right.XeF_{3}\left]\right.^{-}$
(Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)
NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure
Solution:
Species Lone pair on central atom $TeBr^{2 -}$ 1 $BrF_{2}^{+}$ 2 $XeF_{3}^{-}$ 3
Total number of lone pair = 6.
| Species | Lone pair on central atom |
| $TeBr^{2 -}$ | 1 |
| $BrF_{2}^{+}$ | 2 |
| $XeF_{3}^{-}$ | 3 |