Question

The sum of coefficients in the expansion of $(1+3x-3x^2{)}^{1143}$ is equal to

• A. -1
• B. 0
• C. 1
• D. $2^{1143}$
• E. 2

Answer 1

Answer: (C)

Given expansion is ${\left(1+3x-3x^2\right)}^{1143}$
Put $x=1$, we get
${\left[1+3\times 1-3(1{)}^2\right]}^{1143}=[1+3-3{]}^{1143}$
$=(1{)}^{1143}=1$